If the 'ideal' canister burst when hitting the target, the intended effect of the round would be negated. And if that were the case, why do all of the period manuals, and those of the later nineteenth century all state that the cone formed by the balls leaving the canister begins at the muzzle of the piece? As canister had no fuse or bursting charge inside of it, the only explosive device that affects the round is the attached powder cartridge which is ignited in the bore.
If the canister left the tube intact and hit a target there would be little or no effect from the balls inside the canister. If the canister hist the ground with the balls inside there would be little or no force to propel the balls to do any damage to personnel. For all intents and purposes, if the canister does not rupture in the gun tube, it's a dud.