I don't think so. If you're trying to say again that the balls are not released in the bore, then you are incorrect. As I have mentioned before, ballistics and gunnery might be useful to study in this discussion. The force of the explosion will undoubtedly rupture the canister as it was constructed of a sheet of whatever metal or alloy you wish to use in constructing the canister. If it didn't how would you explain how the cone of balls is formed at the muzzle without an explosive charge in the canister itself?